5x^2-12x-2592=0

Solution for 5x^2-12x-2592=0 equation:

5x^2-12x-2592=0

a = 5; b = -12; c = -2592;
Δ = b2-4ac
Δ = -122-4·5·(-2592)
Δ = 51984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{51984}=228$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-228}{2*5}=\frac{-216}{10}
=-21+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+228}{2*5}=\frac{240}{10}
=24
$